Skip to main content
Speclore

Heat Emission Steam Pipes Oil

Reference data and engineering information about heat emission steam pipes oil for heat transfer applications.

heatemissionsteampipes

Overview

Engineering reference data for Heat Emission Steam Pipes Oil in heat transfer.

Key Formulas

Fourier's Law

q=kTq = -k \nabla T

Heat flux proportional to temperature gradient.

Convective Heat Transfer

Q=hA(TsT)Q = hA(T_s - T_\infty)

Heat transfer between surface and fluid.

Stefan-Boltzmann Law

q=εσT4q = \varepsilon \sigma T^4

Radiative heat flux from a surface.

Thermal Resistance

Rth=LkAR_{th} = \frac{L}{kA}

Resistance to heat conduction.

Variables

Symbol Description Unit
qq Heat flux W/m²
kk Thermal conductivity W/(m·K)
hh Convection coefficient W/(m²·K)
TT Temperature K
ε\varepsilon Emissivity
σ\sigma Stefan-Boltzmann constant 5.67×10⁻⁸ W/(m²·K⁴)

Oil Bath Heat Emission Data

Viscosity Classifications

Fluid Type Viscosity (SSU at 100°F)
Light Oils 220 SSU
Heavy Oils 1,100 SSU
Fats 3,833 SSU

Note: Viscosity significantly affects heat transfer performance. Higher viscosity fluids (fats) have substantially lower heat emission rates due to reduced convection and increased thermal resistance.

Coil Surface Area Calculation

The external surface area per unit length of pipe is calculated as:

As=πdLA_s = \pi \cdot d \cdot L

where:

  • dd = outside diameter of the pipe (m)
  • LL = length of pipe section (m)

Heat Emission from Coil

The total heat emission from a submerged steam coil is:

Q=LAsUΔTQ = L \cdot A_s \cdot U \cdot \Delta T

where:

  • LL = total pipe length (m)
  • AsA_s = external surface area per meter length (m²/m)
  • UU = heat emission coefficient (W/m²·°C)
  • ΔT=TsteamToil\Delta T = T_{steam} - T_{oil} = temperature difference (°C)

Example: 2" Coil Heating Fat Tank

Given:

  • Coil length: L=10L = 10 m
  • Outside diameter: d=60.3d = 60.3 mm
  • Steam temperature: Ts=120°CT_s = 120°C
  • Oil temperature: To=40°CT_o = 40°C
  • Heat emission coefficient: U=50U = 50 W/m²·°C (natural convection)

Surface area per meter: As=π×0.0603 m×1 m=0.189 m2/mA_s = \pi \times 0.0603 \text{ m} \times 1 \text{ m} = 0.189 \text{ m}^2/\text{m}

Total heat emission: Q=10×0.189×50×(12040)=7,560 W7.6 kWQ = 10 \times 0.189 \times 50 \times (120 - 40) = 7{,}560 \text{ W} \approx 7.6 \text{ kW}

Interactive Charts

References