Floor Loads Uniformly Concentrated

Overview

Engineering reference data for Floor Loads Uniformly Concentrated in mechanics.

Key Formulas

Newton's Second Law

$F = ma$

Force = mass × acceleration.

Work

$W = Fd\cos\theta$

Work = force × displacement × cos(angle).

Kinetic Energy

$E_k = \frac{1}{2}mv^2$

Energy of motion.

Potential Energy

$E_p = mgh$

Gravitational potential energy.

Variables

Symbol	Description	Unit
$F$	Force	N
$m$	Mass	kg
$a$	Acceleration	m/s²
$v$	Velocity	m/s

Typical Floor Loads

The following table provides typical concentrated and uniformly distributed floor loads for various building applications:

:::note For balconies in hotels or guest houses, the concentrated load of 1.5 kN is applied at the outer edge (as a line load), rather than as a point load. :::

Worked Example

Calculate the load from a 800 kg pallet:

Given:

• Mass: $m = 800 \text{ kg}$
• Gravitational acceleration: $g = 9.81 \text{ m/s}^2$

Applying the load conversion formula:

$F = \frac{m \cdot g}{1000} = \frac{800 \times 9.81}{1000} = 7.8 \text{ kN}$

The load from the 800 kg pallet is 7.8 kN.

Interactive Charts

References

• Original Source